php$name = "001x.gif";$pan = "x";$con = explode($pan,$name);if (count($con)>1):echo $name."中包含".$pan;else:echo $name."中没有包含".$pan;endif;?>http://www.bkjia.com/PHPjc/318093.html www.bkjia.com true http://www.bkjia.com/PHPjc/318093.html TechArticle?php $name="001x.gif"; $pan="x"; $con=explode($pan,$name); if(count($con)1): echo$name."中包含".$pan; else: echo$name."中没有包含".$pan; endif; ?...
php中判断一个字符串包含另一个字符串的方法_PHP教程
•
👁 0人浏览过