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Codeforces Round #274 (Div. 2) C Exams_html/css_WEB-ITnose

题目链接:exams Exams time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Student Valera is an undergraduate student at the University. His end of term exams are approaching and he is to pass exactly n exams. Valera is a smart guy, so he will be able to pass any exam he takes on his first try. Besides, he can take several exams on one day, and in any order. 立即学习 “ 前端免费学习笔记(深入) ”; According to the schedule, a student can take the exam for the i-th subject on the day number ai. However, Valera has made an arrangement with each teacher and the teacher of the i-th subject allowed him to take an exam before the schedule time on day bi (bi? ai ). Thus, Valera can take an exam for the i-th subject either on day ai, or on day bi. All the teachers put the record of the exam in the student's record book on the day of the actual exam and write down the date of the mark as number ai.

35 23 14 2
output input
36 15 24 3
output Note In the first sample Valera first takes an exam in the second subject on the first day (the teacher writes down the schedule date that is 3). On the next day he takes an exam in the third subject (the teacher writes down the schedule date, 4), then he takes an exam in the first subject (the teacher writes down the mark with date 5). Thus, Valera takes the last exam on the second day and the dates will go in the non-decreasing order: 3, 4, 5. In the second sample Valera first takes an exam in the third subject on the fourth day. Then he takes an exam in the second subject on the fifth day. After that on the sixth day Valera takes an exam in the first subject. 大致题意:一个学生,要参加n场考试,但是他想尽快的把所有考试都考完。对于第 i 场考试,老师规定的时间是ai, 他自己安排的时间是bi ,且ai > bi 。现在有一个原则,你的考试时间顺序不能和老师安排的每场考试时间的先后顺序不一致,且这个学生可以在同一时间完成无穷多的考试。问他完成全部考试的最早时间是多少。 解题思路:我最先想到的就是贪心。CF给出的分类是dp,我感觉还是更像贪心。可能没看出来吧,那就先讲讲怎么贪心吧。先按老师给的时间升序给所有考试排序,当时间相等时,按学生给出的时间升序排序。用ans纪录上一次考试结束时间,然后每次都取ai和bi里面最小的bi,如果bi >= ans, ans = bi;否则,ans = ai,然后继续下一次比较。 最后输出ans即可。 AC代码:
#include #include #include #include #include #include #include #include #include #include #include #include using namespace std;#define INF 0x7ffffffftypedef struct{ long long x, y;}T;T t[5005];bool cmp(T a, T b){ if(a.x == b.x) return a.y < b.y; return a.x < b.x;}int main(){ #ifdef sxk freopen("in.txt","r",stdin); #endif int n; while(scanf("%d",&n)!=EOF) { for(int i=0; i

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